If a compound containing only magnesium and oxygen consists of 0.564 g mg and 0.376 g o, what is the compound's empirical formula ...

the Empirical formula of the compound is calculated as follows

find the moles of each element

moles = mass/molar mass

that is Magnesium = 0.564 g / 24 g/mol = 0.0235 moles

For oxygen = 0.376 g / 16 g/mol = 0.0235 moles

find the mole ratio by dividing both moles of by 0.0235 moles

magnesium = 0.0235/0.0235 = 1mole

oxygen = 0.0235 / 0.0235 = 1mole

therefore the empirical formula = MgO