How many moles of na + are present in 343 ml of a 1.27 m solution of na2so4?

Sodium sulfate, Na₂SO₄, is a strong electrolyte. It means that it dissociates into 2 Na⁺ ions and 1 SO₄⁻ ion when dissolved in water. So, for every 1 mole of Na₂SO₄, there is an equivalent amount of 2 mol Na⁺ ions. The solution is as follows:

Moles of Na⁺ = (1.27 mol Na₂SO₄/L) * (1 L/1000 mL) * (343 mL) * (2 mol Na⁺/1 mol Na₂SO₄)

Moles of Na⁺ = 0.87 mol