What is the volume of 55 L of gas initially at 500 K and 4.25 atm when conditions change to STP?

The general gas law equation that is formed by combining the three laws of Boyle, Charle and Guy Lussac is written as:

(PV/T) 1 = (PV/T) 2

STP conditions means that T = 273 kelvin and P = 1 atmospheric pressure

Based on the above rule, we calculate V2 as follows:

(4.25*55) / 500 = (1*V) / 273

V2 = 127.599 liters

Extra notes:

Boyles law: volume and pressure of a certain mass of gas are inversely proportional provided that the temperature is constant

Charle's law: volume and temperature of a certain mass of gas are directly proportional provided that the pressure is constant

Guy Lussac's law: pressure and temperature of a certain mass of gas are directly proportional provided that the volume is constant