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21 December, 17:57

How many mL of a 0.300 M AgNO3 solution will it take to make 500 mL of a 0.100 M AgNO3 solution?

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  1. 21 December, 19:58
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    The answer is 166 mL. You use the formula V1*M1=V2*M2. For what you're given you rearrange the formula to V1=M2*V2/M1 so V1 = (0.500 mL) (0.100 M AgNO3) / (0.300 M AgNO3) = 166 mL
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