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4 May, 23:05

If 10.0 mL of the solution on the right were withdrawn from the 100 mL beaker and diluted again in a similar manner, what is the new concentration? (Recall that a bar over the number

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  1. 5 May, 00:45
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    If the concentration of the starting solution is 10 g/L. The dilution factor is determined by:

    dilution factor = (volume of aliquot / total volume)

    = (10ml / 100ml)

    = 0.10

    The concentration of the resulting solution is:

    0.10 * 10g/L = 1 g/L
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