Ask Question
19 January, 01:47

Zn (s) + cu2 + (aq) →zn2 + (aq) + cu (s). part a under standard conditions, what is the maximum electrical work, in joules, that the cell can accomplish if 51.0 g of copper is plated out?

+3
Answers (1)
  1. 19 January, 04:18
    0
    The energy in Joules is calculated as:

    E = VQ

    At standard conditions, the standard potential or the voltage is equal to 0.76 V. Next, we have to determine Q. The formula is as follows:

    Q = nF, where n is the number of moles electron, while F is the Faraday's constant (96,500 C/mol e)

    From the given reaction, notice that Zn was converted to Zn²⁺, while Cu²⁺ to Cu. So, 1 mol Cu = 2 mol e.

    Q = 51 g Cu (1 mol Cu/63.55 g) (2 mol e/1 mol Cu) (96,500 C/mol e)

    Q = 154885.92 C

    Thus,

    E = (0.76 V) (154885.92 C)

    E = 117,713.3 J
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Zn (s) + cu2 + (aq) →zn2 + (aq) + cu (s). part a under standard conditions, what is the maximum electrical work, in joules, that the cell ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers