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18 January, 19:20

If 89.6 joules of heat are needed to heat 20 g of iron from 30 c to 40 c, what is the specific heat of the iron in j/cg

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  1. 18 January, 19:54
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    Q=cmΔt

    Q=89.6 J

    m=20g

    Δt=t (final) - t (initial) = 40-30=10⁰ C

    89.6 J=c*20g*10⁰ C

    c = 89.6 J / (20g*10⁰ C) = 0.448 J / (g*⁰C)
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