Ask Question
4 September, 17:07

A jar containing only nickels and dimes contains a total of 60 coins. the value of all the coins in the jar is $4.45. solve by elimination to find the amount of nickels and dimes that are in the jar.

+4
Answers (1)
  1. 4 September, 17:49
    0
    1 nickle = 5 cents

    1 dime = 10 cents

    $4.45 = 445 cents

    let

    n = the number of nickles, n>=0

    d = the number of dimes, d>=0

    a jar containing only nickels and dimes contain a total of 60 coins:

    n + d = 60

    the value of all the coins in the jar is $4.45:

    5n + 10d = 445

    by solving the system of equations:

    n + d = 60

    5n + 10d = 445

    we find:

    n = 31 nickels

    d = 29 dimes
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A jar containing only nickels and dimes contains a total of 60 coins. the value of all the coins in the jar is $4.45. solve by elimination ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers