Ask Question
14 December, 22:50

How many grams of MgCl2 will be obtained when 435 mL of 0.300 M HCl react with an excess of Mg (OH) 2?

+4
Answers (1)
  1. 14 December, 23:09
    0
    The grams of Mg (OH) 2 produced is calculated as below

    calculate the moles of HCl produced = molarity xvolume/1000

    = 0.3 x 435/1000 = 0.1305 moles

    write the equation for reaction

    Mg (OH) 2 + 2HCl = MgCl2 + 2H2O

    by use of mole ratio between HCl : MgCl2 which is 2 : 1 the moles of HCl = 0.1305 x1/2 = 0.0653 moles of MgCl2

    mass of MgCl2 = moles x molar mass

    = 0.0653mol x95 g/mol = 6.204 grams of MgCl2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many grams of MgCl2 will be obtained when 435 mL of 0.300 M HCl react with an excess of Mg (OH) 2? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers