What volume does 3.91 moles of nitrogen gas at 5.35 atm and 323 K occupy

Data Given:

Moles = n = 3.91 mol

Pressure = P = 5.35 atm

Temperature = T = 323 K

Volume = V = ?

Formula used: Ideal Gas Equation is used,

P V = n R T

Solving for V,

V = n R T / P

Putting Values,

V = (3.91 mol * 0.0825 atm. L. mol⁻¹. K⁻¹ * 323 K) : 5.35 atm

V = 19.36 L