Solve for the final temperature of the mixture of 400.0 mL of water at 25.00 °C and add 140.0 mL of water at 95.00 °C. Use 1.00 g/mL as the density of water.

(mass) (ΔT) (Cs) = (Cs) (ΔT) (mass)

(140.0g) (95.00-x) (4.184) = (4.184) (x-25.00) (400.0g)

Solve for x

55647.2 - 585.76x = 1673.6x - 41840

-585.76x - 1673.6x = - 41840 - 55647.2

-2,259.36x = - 97,487.2

-2,259.36x / - 2,259.36 = - 97,487.2 / - 2,259.36

X = 43.15