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3 July, 14:17

A titanium cube contains 2.86*1023 atoms. what is the edge length l of the cube? the density of titanium is 4.50 g/cm3. (the volume of a cube is v=l3.)

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  1. 3 July, 15:49
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    When mass Ti = density * volume

    and when moles Ti = mass Ti/molar mass Ti

    ∴ Volume = 2.86 x 10^23 atom * (1 mol Ti / 6.022 x 10^23) * (47.867 g Ti / 1 mol Ti) * (1Cm3 / 4.5 g Ti)

    = 5.05 Cm^3

    when we assume that the sample of Ti is a cube:

    and we assume the length = X

    ∴ V = X^3

    ∴X^3 = 5.05

    ∴X = ∛5.05

    = 1.7 Cm
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