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17 February, 10:40

Calculate the ph of a solution that is 0.278 m in sodium formate (nahco2) and 0.222 m in formic acid (hco2h). the ka of formic acid is 1.77 * 10^-4.

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  1. 17 February, 13:54
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    Use the formula:

    pH = pKa + log[Conjugate base] / [Acid]

    = - log (1.77 * 10^-4) + log[0.278] / [0.222]

    = 3.75 + 0.097

    = 3.84
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