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Chemistry
Stevens
10 February, 22:07
How many moles of o are in 15.0 mol fe (no3) 3?
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Zavier Barnes
10 February, 23:48
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N[Fe (NO₃) ₃]=15.0 mol
n (O) = 3*3*n[Fe (NO₃) ₃]=9n[Fe (NO₃) ₃]
n (O) = 9*15.0=135.0 mol
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