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18 September, 07:43

For the reaction so3 + h2o h2so4, calculate the percent yield if 500. g of sulfur trioxide react with excess water to produce 575 g of sulfuric acid.

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  1. 18 September, 07:51
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    The % yield if 500 g of sulfur trioxide reacted with excess water to produce 575 g of sulfuric acid is calculated using the below formula

    % yield = actual yield / theoretical yield x100

    actual yield = 575 grams

    to calculate theoretical yield

    find the moles of SO3 used = mass/molar mass

    = 500g / 80 g/mol = 6.25 moles

    SO3+H2O=H2SO4

    by use of mole ratio of SO3 : H2SO4 which is 1:1 the moles of H2SO4 is also = 6.25 moles

    the theoretical yield of H2SO4 is therefore = moles / molar mass

    = 6.25 x98 = 612.5 grams

    %yield is therefore = 575 g/612 g x100 = 93.9 %
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