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3 October, 23:39

Determine the molality of an aqueous solution that is 15.5 percent urea by mass.

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  1. 3 October, 23:49
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    15.5% by mass is equivalent 15.5 g urea in 100 g solution or 155 g urea in 1 kg solution.

    we know that molality = moles solute / kg solvent

    moles solute = 155 g / 60 g/mol = 2.58 moles urea

    Since there are 155 g urea in 1000g solution, hence the solvent is 845 g or 0.845 kg

    So:

    molality = 2.58 / 0.845 = 3.06 m
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