Consider the reaction, 2 d (g) + 3 e (g) + f (g) = > 2 g (g) + h (g) when h is increasing at 0.64 mol/ls, how quickly is e decreasing? give your answer to 3 decimal places.

Question

Chemistry

Armani Wang

1 September, 18:25

Consider the reaction, 2 d (g) + 3 e (g) + f (g) = > 2 g (g) + h (g) when h is increasing at 0.64 mol/ls, how quickly is e decreasing? give your answer to 3 decimal places.

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Answers (1)

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Zachariah Schneider · Answer 1

Answer is: 1,92 mol/L·s.

Chemical reaction: 2D (g) + 3E (g) + F (g) → 2G (g) + H (g).

H is increasing at 0,64 mol/L· s.

From chemical reaction n (H) : n (E) = 1 : 3.

0,64 mol : n (E) = 1 : 3.

n (E) = 1,92 mol.

E is decreasing at 1,92 mol/L·s.