A substance has a solubility of 350 ppm. how many grams of the substance are present in 1.0l of a saturated solution

Since the given solubility is 350 ppm, convert it first with fraction of solubility. by dividing the solubility with 10^6

S = 350 / 10^6

s = 3.5 x 10^-4

the multiply it to the total solution to calculate the amount of substance present

m = (3.5 x 10^-4) (1.01)

m = 3.535 x 10^-4 g of the substance present