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19 May, 12:33

Tear gas has the composition 40.25% carbon, 6.19% hydrogen, 8.94% oxygen, 44.62% bromine. what is the empirical formula of this compound?

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  1. 19 May, 12:49
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    Calculating the moles and the moles ratio of the elements gives us the ratio of atoms in each element. Converting the percentage of element into grams 40.25% carbon = 40.25/100 =.4025 * 100 g of carbon = 40.25g of C 6.19% hydrogen = 6.19/100 =.0619 * 100g g of hydrogen = 6.19g of H 8.94% oxygen = 8.94/100 =.0819 * 100 g of oxygen = 8.19g of O 44.62% bromine = 44.62/100 =.4462 * 100 g of bromine = 44.62g of Br Converting the grams of element into moles (48.38 g C) (1 mol / 12.10 g C) = 4.028 mol C (8.12 g H) (1 mol / 1.008 g H) = 8.056 mol H (53.38 g O) (1 mol / 16.00 g O) = 3.336 mol O (44.62g of Br) (0.012515018021626 moles) = 0.55842 mol Br Calculating the moles ratio of elements by dividing the small number of moles of an element 4.028 mol C / 0.55842 = 7.2 mol C x 5 = 36 mol C 8.056 mol H / 0.55842 = 14.42 mol H = 72 mol H 3.336 mol O / 0.55842 = 5.97 mol O = 30 mol O 0.55842 mol Br / 0.55842 = 1mol Br = 5 mol Br So the empirical formula is (C6H12O5) 6Br5
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