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26 July, 15:47

Suppose the half-life of an element is 10 years. How many half-lives will it take before only about 6% of the original sample remains? 3 half-lives 4 half-lives 5 half-lives 6 half-lives

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  1. 26 July, 19:05
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    We can solve this problem by using the equation as shown: A=Aoe^ - (ln2/t) T where A is the final amount (0.06 gram), Ao is the initial amount (1g * assumed), t is the half-life (10 years) and lastly T time elapsed (required). Plug in the values in the equation and you should get 40.5 years and this is approximately 4 half-lives.
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