Calculate the molarity of 0.700 mol of na2s in 1.05 l of solution.

Question

Chemistry

Arturo Mcknight

5 April, 21:33

Calculate the molarity of 0.700 mol of na2s in 1.05 l of solution.

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Giovani Francis · Answer 1

Molarity is the amount of solute molecule (in moles) per 1L of solvent. In this case, the solute is 0.7mol Na2S and the solvent volume is 1.05L. Since the unit in this problem is already mol and L then you don't need to do any conversion of the units. The calculation would be:

molarity = mol of solute / (1L / volume of solvent)

molarity = 0.7 mol / (1L / 1.05L) = 0.67M