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11 March, 07:05

How many moles of CaCl2 have you delivered to the flask if you add 20.53mL of 0.511 M CaCl2 from the buret

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  1. 11 March, 09:47
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    Answer is: 0,0105 moles of calcium chloride have delivered to the flask.

    V (CaCl₂) = 20,53 mL : 1000 mL/L = 0,02053 L.

    c (CaCl₂) = 0,511 M = 0,511 mol/L.

    n (CaCl₂) = c (CaCl₂) · V (CaCl₂).

    n (CaCl₂) = 0,511 mol/L · 0,02053 L.

    n (CaCl₂) = 0,0105 mol.
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