How many milliliters of a 1.25 molar HCL solution would be needed to react completely with 60 g of calcium metal

Ca+2HCl - - > CaCl2 + H2

Ca + 2HCl = CaCl₂ + H₂

m (Ca) = 60 g

c=1.25 mol/l

M (Ca) = 40g/mol

v-?

m (Ca) / M (Ca) = m (HCl) / [2M (HCl) ]=n (HCl) / 2

n (HCl) = 2m (Ca) / M (Ca)

n (HCl) = cv

cv=2m (Ca) / M (Ca)

v=2m (Ca) / {cM (Ca) }

v=2·60g/mol/{1.25mol/l·40g/mol}=2.4 l = 2400 ml

2400 milliliters of a 1.25 molar HCl solution would be needed