Ask Question
18 June, 03:59

What is the ph of a solution of 0.450 m kh2po4, potassium dihydrogen phosphate?

+3
Answers (1)
  1. 18 June, 04:10
    0
    PKa = - log (Ka) = log [HPO4 (2-) ] - log[H+]^2 = - log (4.2*10^-13)

    pH = - log [H+]

    - log [H+]^2 = - 2 log [H+]

    2pH = - log (4.2*10^-13) - log [HPO4 (2-) ]

    2pH = - log (4.2*10^-13) - log (0.550)

    pH = 6.32
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the ph of a solution of 0.450 m kh2po4, potassium dihydrogen phosphate? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers