What is the mass of silver in 4.3g AgNO3?

4.22 grams.

1. First find out how much AgNO3 weighs with one mole (107.87 g Ag + 14.007 g N + 48 g O = 169.89 grams)

2. Find the percent of Ag you have. So, (107.87 g/mol Ag) / (169.89 g/mol AgNO3) = 0.63 * 100 = 63%.

3. If you have 6.7 grams total, you know 63% of it is going to be silver, so just multiply 6.7 grams by. 63 and you get 4.22 g Ag