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26 May, 17:35

What volume of a 1.0 M HCl is required to completely neutralize 25.0 ml of a 1.0 M KOH?

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  1. 26 May, 21:09
    0
    x 0,025

    HCl+KOH--> KCl + H2O

    1 1

    c=1M

    V=25ml=0,025l (you need the volume to be in l)

    c = n/V

    n=c*V

    n=1*0,025=0,025 m KOH

    x=0,025m

    c=1 M

    V=n/c

    V=0,025/1=0,025l=25ml HCl
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