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3 January, 14:08

Suppose you wanted to dissolve 106 g of Na2CO3 in enough H2O to make 6.00 L of solution.

(1) What is the molar mass of Na2CO3? (2) What is the molarity of this solution?

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Answers (2)
  1. 3 January, 16:16
    0
    M (Na2CO3) = 2M (Na) + M (C) + 3M (O)

    =2 (23) + 12+3 (16)

    =46+12+48

    =106 g/mol

    the molar mass of Na2CO3 is 106 g/mol

    m=106g M=106 g/mol n=m/M

    n=m/M n=106/106 n=1mol
  2. 3 January, 16:41
    0
    Molar mass of Sodium Carbonate is 106, molarity is 1.0M. Seriously just look at a periodic table this is easy stuff.
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