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9 May, 06:03

A container of oxygen with a fixed volume has a pressure of 13.0 atm at a temperature of 20 °C. What will the pressure of the oxygen be if the container is heated to 102 °C? A. 12.4 atm B. 15.4 atm C. 16.6 atm D. 18.6 atm

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  1. 9 May, 09:25
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    Given:

    P1 = 13.0 atm

    T1 = 20 °C

    T2 = 102 °C

    Required:

    P2 of oxygen

    Solution:

    At constant volume, we can apply Gay-Lussac’s law of pressure and temperature relationship

    P1/T1=P2/T2

    (13.0 atm) / (20 °C) = P2 / (102 °C)

    P2 = 66.3 atm

    The answer is not in the choices given.
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