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4 November, 22:01

Enough of a monoprotic acid is dissolved in water to produce a 0.0136 M solution. The pH of the resulting solution is 2.45. Calculate the Ka for the acid.

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  1. 5 November, 01:47
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    Using pH to determine [H+]

    10^-pH = 10^-2.45 = 2.1 x 10^-3

    Now,

    Ka=[H=][A-]/[HA]

    So,

    (2.1 x 10^-3) ^2/0.0136 - (2.1 x 10^-3)

    Ka=2.5 x 10^4
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