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9 January, 16:40

How many molecules of aspirin C9H804 are there in 100.0 MG tablets of aspirin

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Answers (2)
  1. 9 January, 16:50
    0
    3.34*10³⁰ molecules of C₉H₈O₄

    Explanation:

    Let's determine the molar mass of aspirin:

    C₉H₈O₄ → 12 g/mol. 9 + 1g/mol. 8 + 16g/mol. 4 = 180 g/mol

    Let's convert the mass from g to mg → 180 g. 1000 mg/1g = 180000 mg

    = 1.8*10⁵ mg

    Now, we make a rule of three:

    In 1.8*10⁵ mg of aspirin (1 mol) we have 6.02*10²³ molecules

    In 100 mg of aspirin, we may have (100. 6.02*10³) / 1.8*10⁵ = 3.34*10³⁰ molecules
  2. 9 January, 17:40
    0
    In 100 mg aspirin there are 3.34*10^20 molecules

    Explanation:

    Step 1: Data given

    Mass of aspirin = 100.0 mg = 0.100 grams

    Molar mass of aspirin = 180.158 g/mol

    Number of Avogadro = 6.022*10^23 molecules / mol

    Step 2: Calculate moles

    Moles aspirin = mass aspirin / molar mass aspirin

    Moles aspirin = 0.100 grams / 180.158 g/mol

    Moles aspirin = 5.55 * 10^-4 moles

    Step 3: Calculate molecules aspirin

    Molecules = moles * number of Avogadro

    Molecules = 5.55 * 10^-4 moles * 6.022 * 10^23 molecules / mol

    Molecules = 3.34*10^20 molecules

    In 100 mg aspirin there are 3.34*10^20 molecules
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