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26 May, 03:29

If a pork roast must absorb 1500 kJkJ to fully cook, and if only 14% of the heat produced by the barbeque is actually absorbed by the roast, what mass of CO2CO2 is emitted into the atmosphere during the grilling of the pork roast?

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  1. 26 May, 04:38
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    You need to know the amount of heat generated by the combustion reaction.

    Assuming propane as fuel, you can use thiis dа ta:

    C3H8 (g) + 5O2 (g) - --3CO2 (g) + 4H2O (g) ΔH = - 2217 KJ

    So when 3 moles of CO2 is emmitted 2217 kJ of heat is produced.

    The molar wegiht of CO2 is 12 g/mol + 2 * 16 g/mol = 44 g/mol.

    Then 3 mol * 44 g / mol = 132 g of CO2 are produced with 2217 kJ of heat.

    Now you have to calculate how much energy you need to produce if only 12% is abosrbed by the pork

    Energy absorbed by the pork = 12% * total energy = >

    total energy = energy absorbed by the pork / 0.12 = 1700 kJ / 0.12 = 14,166.67 kJ.

    Now, state the proportion:

    132 g CO2 / 2217 kJ = x / 14,166.7 kJ = >

    x = 14,166.67 * 132 / 2217 = 843.48 g CO2.

    Answer: 843 g of CO2
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