A mixture of krypton and hydrogen gas is expanded from a volume of 30.0L to a volume of 82.0L, while the pressure is held constant at 14.0atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

Question

Chemistry

Roxie

9 January, 12:54

A mixture of krypton and hydrogen gas is expanded from a volume of 30.0L to a volume of 82.0L, while the pressure is held constant at 14.0atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

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Answers (1)

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Angelo Ray · Answer 1

The work done = - 73.8 kJ

Explanation:

Step 1: Data given

Volume of 30.0 l expanded tot 82.0 L

Pressure = constant = 14.0 atm

w = - P * (change in V)

w = - 14 atm * (82-30)

w = - 728 L*atm = - 728 * 101.325 J / 1 L*atm) = - 73764.6 J = - 73.8 kJ

The sign is - meaning that work is done on the surroundings. The system is losing energy equal to the work done on it.