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29 May, 03:32

One thousand kilograms per hour of a mixture of benzene and toluene that contains 50% by mass are seperated by distallation into two fractions.

The mass flow of benzene in the top stream is 450kg benzne/hour, and toluene in the bottom stream is 475 kg toulene/hour.

Write the material balance on benzene and toluene to calculate the unknown components in the output stream.

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  1. 29 May, 06:15
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    50 kg benzene/hour and 25 kg toluene/hour

    Explanation:

    According to Lavoisier's law, the mass can't be created either destroyed, thus, the material in the input must be equal to the material in the output + the material formed if there's a reaction + the accumulation in the reactor.

    Thus, for bezene:

    minput = mtop + mbottom

    If 50% of the mass is composed by each substance:

    0.5*1000 = 450 + mbottom

    500 = 450 + mbottom

    mbottom = 50 kg benzene/hour

    For toluene:

    minput = mtop + mbottom

    0.5*1000 = mtop + 475

    mtop = 500 - 475

    mtop = 25 kg toluene/hour
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