Ask Question
26 February, 07:31

Consider four different samples: aqueous LiBr, molten LiBr, aqueous AgBr, and molten AgBr. Current run through each sample produces one of the following products at the cathode: solid lithium, solid silver, or hydrogen gas. Match each sample to its cathodic product. Math following to Cathoid Products-Solid Lithium, Solid Silver, and Hydrogen GasSamples1. Aqueous LiBr2. Molten LiBr3. Aqueous AgBr4. Molten AgBr

+2
Answers (1)
  1. 26 February, 08:19
    0
    a) Aqueous LiBr = Hydrogen Gas

    b) Aqueous AgBr = solid Ag

    c) Molten LiBr = solid Li

    c) Molten AgBr = Solid Ag

    Explanation:

    a) Aqueous LiBr

    This sample produces Hydrogen gas, because the H + (conteined in the water) has a reduction potential higher than the Li + from the salt. Therefore the hydrogen cation will reduce instead of the lithium one and form the gas.

    b) Aqueous AgBr

    This sample produces Solid Ag, because the Ag + has a reduction potential higher than the H + from the water. Therefore the silver cation will reduce instead of the hydrogen one and form the solid.

    c) Molten LiBr

    In a molten binary salt like LiBr there is only one cation present in the cathod. In this case the Li+, so it will reduce and form solid Li.

    c) Molten AgBr

    The same as the item above: there is only one cation present in the cathod. In this case the Ag+, so it will reduce and form solid Ag.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Consider four different samples: aqueous LiBr, molten LiBr, aqueous AgBr, and molten AgBr. Current run through each sample produces one of ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers