If an element with the valence configuration 4s23d6 loses 2 electron (s), these electron (s) would be removed from the subshell (s).

B. An element with the valence electron configuration 2s22p5 would form a monatomic ion with a charge of.

In order to form this ion, the element will (lose/gain) electron (s) from/into the subshell (s).

Question

Chemistry

Gianni Fox

6 August, 10:52

If an element with the valence configuration 4s23d6 loses 2 electron (s), these electron (s) would be removed from the subshell (s).

B. An element with the valence electron configuration 2s22p5 would form a monatomic ion with a charge of.

In order to form this ion, the element will (lose/gain) electron (s) from/into the subshell (s).

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Answers (1)

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Liliana Krause · Answer 1

A. 4s subshell.

B. An element with the valence electron configuration 2s² 2p⁵ would form a monatomic ion with a charge of - 1.

In order to form this ion, the element will gain 1 electron into the 2p subshell.

Explanation:

A. An element with the valence electron configuration 4s² 3d⁶ is a transition metal. The electrons lost will be the ones from the last level (4), that is, the 4s subshell. The electron configuration of the ion will be 4s⁰ 3d⁶.

B. An element with the valence electron configuration 2s² 2p⁵ is a nonmetal with 2 + 5 = 7 electrons in its valence shell. To complete its octet, it will gain 1 electron into the subshell 2p. Now having an extra electron, it will have a charge of - 1.