What is the oxidation state, d electron count, and coordination number respectively of the cobalt ion in [CoBr (NH3) 4]PO4? What is the oxidation state, d electron count, and coordination number respectively of the cobalt ion in [CoBr (NH3) 4]PO4? + 3, 6, and 5 + 3, 6, and 6 + 4, 5, and 6 + 4, 5, and 5 0, 9, and 6

Question

Chemistry

Rambler

13 December, 07:22

What is the oxidation state, d electron count, and coordination number respectively of the cobalt ion in [CoBr (NH3) 4]PO4? What is the oxidation state, d electron count, and coordination number respectively of the cobalt ion in [CoBr (NH3) 4]PO4? + 3, 6, and 5 + 3, 6, and 6 + 4, 5, and 6 + 4, 5, and 5 0, 9, and 6

+1

Answers (1)

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Ryan Ali · Answer 1

The correct option is: + 4, 5, and 5

Explanation:

A coordination complex consists of a central metal atom or ion bonded to ligands by coordinate covalent bonds. The ligands and the central metal together form the coordination sphere.

[CoBr (NH₃) ₄]PO₄

Central metal atom - Co

Coordination sphere consists of 1 Br⁻ and 4 NH₃ ligands

Therefore, the coordination number = 5

Let the oxidation state of Co = x

Oxidation state of Br⁻ ligand = (-1)

Oxidation state of NH₃ ligand = 0

Oxidation state of PO₄³⁻ ligand = - 3

∴ x + (-1) * 1 + 0 * 4 + (-3) * 1 = 0

⇒ x = + 4

Oxidation state of Co = + 4

Electron configuration of Co in ground state: [Ar] 3d⁷ 4s²

Electron configuration of Co in + 4 oxidation state: [Ar] 3d⁵ 4s⁰

Therefore, the number of d electrons in cobalt ion = 5