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14 December, 01:53

A mixture of krypton and methane gases, at a total pressure of 775 mm Hg, contains 4.77 grams of krypton and 2.38 grams of methane. What is the partial pressure of each gas in the mixture?

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  1. 14 December, 03:44
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    Partial pressure of Kr → 214.06 mmHg

    Partial pressure of CH₄ → 560.5 mmHg

    Explanation:

    To determine partial pressure we can work with mole fraction.

    Mole fraction = moles of gas / Total gas = Partial pressure gas / Total pressure

    Let's determine the moles of each compound (mass / molar mass)

    4.77 g / 83.80 g/mol = 0.0569 moles of Kr

    2.38 g / 16 g/mol = 0.149 moles of CH₄

    Total moles = 0.0569 + 0.149 → 0.206

    Partial pressure of Kr → (0.0569/0.206). 775 mm Hg = 214.06 mmHg

    Partial pressure of CH₄ → (0.149/0.206). 775 mm Hg = 560.5 mmHg
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