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24 August, 12:34

A sample of krypton gas in a container of volume 1.90 L exerts a pressure of 0.553 atm at 21 Celsius. How many moles of gas are present?

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Answers (2)
  1. 24 August, 12:49
    0
    0.044 mole

    Explanation:

    Data obtained from the question include:

    V (volume) = 1.90 L

    P (pressure) = 0.553 atm

    T (temperature) = 21°C = 21 + 273 = 294K

    R (gas constant) = 0.082atm. L/Kmol

    n (number of mole of krypton) = ?

    Using the ideal gas equation PV = nRT, the number of mole of krypton can obtained as illustrated below:

    PV = nRT

    n = PV / RT

    n = (0.553 x 1.9) / (0.082x294)

    n = 0.044 mole

    Therefore, 0.044 mole of krypton is present in the container.
  2. 24 August, 13:35
    0
    pv = nRT

    n = PV/RT

    n = 0.553*1.90/0.0821*294

    n=1.0507/24.1374

    n=0.0435mol
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