A 100.0 mL bubble of hot gases at 225 °C and 1.80 atm escapes from an

active volcano, what is the new volume of the bubble outside the volcano

where the temperature is - 25 °C and the pressure is 0.80 atm?

The new or final volume is 112.1 mL.

Explanation:

Given dа ta:

Initial temperature = 225 °C (225 °C + 273.15 = 498.15 K)

Initial pressure = 1.80 atm

Initial volume = 100.0 mL

Final temperature = - 25 °C (-25 °C + 273.15 = 248.15 K)

Final pressure = 0.8 atm

Final volume = ?

Formula

P₁V₁ / T₁ = P₂V₂ / T₂

Solution:

V₂ = P₁V₁. T₂ / T₁. P₂

V₂ = 1.80 atm. 100 mL. 248.15 K / 498.15 K. 0.8 atm

V₂ = 44667 mL / 398.52

V₂ = 112.1 mL