How many moles are there in 1.505 X10^24 molecules of sucrose (C12H22O11) ?

Answer: 2.5 moles C12H22O11

Explanation: To solve the following problem use Avogadro's number.

1.505x10²⁴ molecules C12H22O11 x 1 mole C12H22O11 / 6.022x10²³ molecules C12H22O11

= 2.5 moles C12H22O11

Cancel out molecules of C12H22O11

Number of moles = No of mokecules / Avigadro's number

Avigadro's number = 6.022*10 (23)

No of moles = 1.505*10 (24) / 6.022*10 (23)

No of moles = 2.49 = 2.5mol

The number of mole is 2.5mol