Beaker A contains 2.06 mol of copper, and Barker B contains 222 grams of silver. Which beaker the larger number of atom?

The number of copper atoms 12.405 * 10²³ atoms.

The number of silver atoms 13.13 * 10²³ atoms.

Beaker B have large number of atoms.

Explanation:

Given dа ta:

In beaker A

Number of moles of copper = 2.06 mol

Number of atoms of copper = ?

In beaker B

Mass of silver = 222 g

Number of atoms of silver = ?

Solution:

For beaker A.

we will solve this problem by using Avogadro number.

The number 6.022*10²³ is called Avogadro number and it is the number of atoms in one mole of substance.

While we have to find the copper atoms in 2.06 moles.

So,

63.546 g = 1 mole = 6.022*10²³ atoms

For 2.06 moles.

2.06 * 6.022*10²³ atoms

The number of copper atoms 12.405 * 10²³ atoms.

For beaker B:

107.87 g = 1 mole = 6.022*10²³ atoms

For 222 g

222 g / 101.87 g/mol = 2.18 moles

2.18 mol * 6.022*10²³ atoms = 13.13 * 10²³ atoms