A large cylindrical tank contains 0.750 m3 of nitrogen gas at 27°C and 7.50 * 103 Pa (absolute pressure). The tank has a tight-fitting piston that allows the volume to be changed. What will be the pressure if the volume is decreased to 0.480 m3 and the temperature is increased to 157°C?

Answer: The answer is 68142.4 Pa

Explanation:

Given that the initial properties of the cylindrical tank are:

Volume V1 = 0.750m3

Temperature T1 = 27C

Pressure P1 = 7.5*10^3 Pa = 7500Pa

Final properties of the tank after decrease in volume and increase in temperature:

Volume V2 = 0.480m3

Temperature T2 = 157C

Pressure P2 = ?

Applying the gas law equation (Charles and Boyle's laws combined)

P1V1/T1 = P2V2/T2

(7500 * 0.750) / 27 = (P2 * 0.480) / 157

P2 = (7500 * 0.750 * 157) / (0.480 * 27)

P2 = 883125/12.96

P2 = 68142.4Pa

Therefore the pressure of the cylindrical tank after decrease in volume and increase in temperature is 68142.4Pa