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29 May, 06:37

At 1000 K, a sample of pure NO2 gas decomposes. 2 NO2 (g) equilibrium reaction arrow 2 NO (g) + O2 (g) The equilibrium constant KP is 158. Analysis shows that the partial pressure of O2 is 0.99 atm at equilibrium. Calculate the pressure of NO and NO2 in the mixture.

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  1. 29 May, 10:30
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    0.1575 atm

    Explanation:

    we have that equilibrium constant Kp = (PNO) ₂PO₂ / (PNO₂) ₂

    and it is given to be 158

    ==> Kp = (PNO) ₂PO₂ / (PNO₂) ₂ = 158

    we also have that the partial pressure of O2 (PO₂) = 0.99 atm

    Therefore,

    PO₂ = 0.99 atm = => PNO = 2 (0.99 atm) = 1.98 atm (based on the stoichiometry)

    ==> PNO₂ = √ ((PNO) ₂PO₂ / 158) atm = √ ((1.98) * 2 (0.99) / 158) atm = 0.1575 atm
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