For the neutralization reaction: 2 HCl + Ca (OH) 2 - > CaCl2 + 2H20, how many

grams of Ca (OH) 2 are required to produce 135 grams CaCl2? The reaction

occurs in the presence of excess HCL.

60.29

9049

1359

180 g

Submit

Law of Conservation of Matter

90g of Ca (OH) 2

Explanation:

2HCl + Ca (OH) 2 - > CaCl2 + 2H20

Molar Mass of Ca (OH) 2 = 40 + 2 (16 + 1) = 40 + 2 (17) = 40 + 34 = 74g/mol

Molar Mass of CaCl2 = 40 + (2 x 3.5) = 40 + 71 = 111g/mol

From the equation,

74g of Ca (OH) 2 produced 111g of CaCl2.

Therefore, Xg of Ca (OH) 2 will produce 135g of CaCl2 i. e

Xg of Ca (OH) 2 = (74 x 135) / 111 = 90g.

Therefore, 90g of Ca (OH) 2 are required to produce 135g of CaCl2