Sulfuric acid is a polyprotic acid. Write balanced chemical equations for the sequence of reactions that sulfuric acid can undergo when it's dissolved in water.

H₂SO₄ (aq) + H₂O (l) → HSO₄⁻ (aq) + H₃O⁺ (aq)

HSO₄⁻ (aq) + H₂O (l) ⇄ SO₄⁻² (aq) + H₃O⁺ (aq) Ka

Explanation:

The sulfuric acid is a dyprotic acid.

It is a considered a strong acid but only the first deprotonation is strong.

Second deprotonation is totally weak

That's why we have equilibrium when it release the second proton.

Since a deprotonation is treated for a weak acid, the acid is considered not to completely dissociate, that's why the equilibrium