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2 January, 13:05

Hydrogen gas and oxygen gas combine according to this reaction: 2H2 (g]+O2 (g]→2H2O (l]At STP, a chemist mixes 3.74 L of hydrogen gas with excess oxygen gas. How many liters of oxygen gas will react?

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Answers (2)
  1. 2 January, 16:07
    0
    1.87 L of O2 will react

    Explanation:

    Step 1: Data given

    Volume of H2 = 3.74 L

    Step 2: The balanced equation

    2H2 (g) + O2 (g) →2H2O (l)

    Step 3: Calculate moles H2

    1 mol = 22.4 L

    3.74 L = 0.167 moles

    Step 4: Calculate moles O2

    For 2moles H2 we need 1 mol O2 to produce 2 moles H2O

    For 0.167 moles H2 we need 0.167/2 = 0.0835 moles O2

    Step 5: Calculate volume O2

    1 mol = 22.4 L

    0.0835 moles = 22.4 * 0.0835 = 1.87 L

    1.87 L of O2 will react
  2. 2 January, 16:36
    0
    1.47 Liters of O₂ were reacted

    Explanation:

    The reaction is:

    2H₂ (g) + O₂ (g) → 2H₂O (l)

    As we have the volume of hydrogen we need to work with denstiy to determine the moles that have reacted.

    Density = mass / volume

    Density. volume = mass → 0.071 g/L. 3.74L = 0.265 g

    We determine the moles of H₂ → 0.265 g. 1mol/2g = 0.132 moles

    In the reaction, ratio is 2:1. We make a rule of three:

    2 moles of H₂ need 1 mol of O₂ to react

    Then, 0.132 moles would need (0.132.1) / 2 = 0.066 moles of O₂

    In order to determine the volume we need the oxygen's density but, we have to convert the mass to moles, firstly.

    0.066 moles. 32 g / 1mol = 2.12 g

    Then oxygen's density = oxygen's mass / oxygen's volume

    Oxygen's volume = oxygen's mass / oxygen's density

    O₂ volume = 2.12 g / 1.43 g/L = 1.47 L
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