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11 July, 12:23

ogen gas and nitrogen gas react to produce ammonia. How many liters of ammonia can be produced from 2 liters of hydrogen gas and 2 liters of nitrogen gas at STP

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  1. 11 July, 13:53
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    From 2 liters of hydrogen gas and 2 liters of nitrogen gas, we can produce 1.10 L of ammonia.

    Explanation:

    First of all, think the ballanced equation:

    3H₂ + N₂ → 2NH₃

    We must know the density of products and reactants to solve this.

    Density shows the relation between mass and volume of a compound, like this:

    ρ = mass / volume

    ρ H₂ = 0.071 g/L

    ρ N₂ = 1.2506 g/L

    ρ NH₃ = 0.73 g/L

    Let's calculate the mass of reactants

    mass of H₂ = ρ H₂. volume H₂

    mass of H₂ = 0.071 g/L. 2L → 0.142 g

    mass of N₂ = ρ N₂. volume N₂

    mass of N₂ = 1.2506 g/L. 2L → 2.50 g

    Now, let's calculate the moles

    mass H₂ / molar mass H₂ = moles

    0.142 g / 2g/m = 0.071 moles

    mass N₂ / molar mass N₂ = moles

    2.50 g / 28 g/m = 0.089 moles

    As the ratio between products is 3:1, it's easy to see that the limiting reactant is H₂. Let's see

    1 mol of N₂ needs to react with 3 moles of H₂

    0.089 mol of N₂ need to react with (0.089.3) / 1 = 0.267

    I only have 0.071 moles.

    The ratio between H₂ and NH₃ is 3:2 so the rule of three is:

    3 moles of H₂ __ are necessary to make 2 moles of ammonia

    0.071 moles of H₂ _ are necessary to make (0.071.2) / 3 = 0.0473 moles

    Let's convert this moles in mass, with the molar mass

    Moles. Molar mass = mass

    0.0473 moles. 17 g/m = 0.804 g

    Now, with the density we can know the volume:

    ρ NH₃ = 0.73 g/L

    Volume NH₃ = mass NH₃ / ρ NH₃

    Volume NH₃ = 0.804 g/0.73 g/L

    Volume NH₃ = 1.10L
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