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4 February, 20:11

A sample of propane occupies 274 L at 133 kPa and 316K. Find its volume at 98 kPa and 616K.

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  1. 4 February, 23:10
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    725L

    Explanation:

    From the question given, we obtained the following information:

    V1 = 274L

    P1 = 133kPa

    T1 = 316k

    P2 = 98kPa

    T2 = 616K

    V2 = ?

    We can obtain the new volume by doing the following:

    P1V1/T1 = P2V2/T2

    133 x 274 / 316 = 98x V2 / 616

    Cross multiply to express in linear form:

    316 x 98 x V2 = 133 x 274 x 616

    Divide both side by 316 x 98

    V2 = (133 x 274 x 616) / 316 x 98

    V2 = 725L

    Therefore, the new volume is 725L
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