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19 September, 05:11

Calculate the amount of time required to raise temperature of 0.50 liter of water from

0.0° C to 10.0° C if heat energy is supplied at a rate of 1100 joules per second

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Answers (1)
  1. 19 September, 06:40
    0
    19 seconds

    Explanation:

    Heat energy was supplied and used to heat 0.50 liters of water from 0°C to 10°C.

    This means water gained heat energy that was supplied.

    Therefore;

    Heat supplied = Heat gained by water

    We are required to calculate the time taken to raise the temperature of water from 0°C to 10°C.

    Step 1: Calculate the heat gained by water

    Quantity of heat = Mass * specific heat capacity * change in temperature

    Density of water 1 g/ml

    Volume of water is 500 mL

    Therefore, since Mass = density * volume

    The mass of water = 500 g

    Change in temperature = 10° C

    Specific heat capacity of water = 4.18 J/g/°C

    Thus;

    Quantity of heat = 500 g * 4.18 J/g/°C * 10

    = 20,900 Joules

    Step 2: Heat supplied by a heater

    Heat supplied = Power * time

    Power = 1100 J/s

    Assuming the time required is x

    Heat supplied = 1100x Joules

    Step 3: Time required

    Remember; heat supplied = heat gained by water

    Therefore;

    1100x joules = 20,900 Joules

    x = 20,900/1100

    = 19 seconds

    Therefore, the time required to raise the temperature of water from 0°C to 10°C is 19 seconds.
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