How many grams of Cl are in a 38.0-g sample of CFCl3

Question

Chemistry

Buffie

8 July, 14:56

How many grams of Cl are in a 38.0-g sample of CFCl3

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Answers (2)

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Jaime · Answer 1

38.0 g CF2Cl2) / (120.9135 g CF2Cl2/mol) x (2 mol Cl / 1 mol CF2Cl2) x (35.4532 g Cl/mol) =

22.3 g Cl in CF2Cl2

(38.0 g CFCl3) / (137.3681 g CFCl3/mol) x (3 mol Cl / 1 mol CFCl3) x (35.4532 g Cl/mol) =

29.4 g Cl in CFCl3

(38.0 g C2F3Cl3) / (187.3756 g C2F3Cl3/mol) x (3 mol Cl / 1 mol C2F3Cl3) x (35.4532 g Cl/mol) =

21.6 g Cl in C2F3Cl3

(38.0 g CF3Cl) / (104.4589 g CF3Cl/mol) x (1 mol Cl / 1 mol CF3Cl) x (35.4532 g Cl/mol) =

12.9 g Cl in CF3Cl

Marina Wood · Answer 2

Answer: 29.4 g Cl in CFCl3

Explanation: (38.0 g CFCl3) / (137.3681 g CFCl3/mol) x (3 mol Cl / 1 mol CFCl3) x (35.4532 g Cl/mol) =

29.4 g Cl in CFCl3